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Let's assume that the resistance is 1 Ω and the time is 1 second.
However, in practice, there will be some resistance and the current will decay over time according to the formula I(t) = I0 e^(-R/L t), where I0 is the initial current, R is the resistance, L is the inductance, and t is the time. Then the current will be I = V/R = 1/0 = ∞ (in theory). Let's assume that the initial voltage is 1 V and the resistance of the line is negligible. Since there is no voltage source, we assume that the line is initially charged to a certain voltage and then disconnected from the source, so that the current will decay over time due to the inductance of the line. Calculate the current flowing through the coaxial line. Calculate the inductance of the coaxial line using the formula L = μ0/2π * ln(b/a), where μ0 is the permeability of free space, b is the outer radius of the outer conductor, and a is the inner radius of the inner conductor.Ģ.
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